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6x^2+24x-537.6=0
a = 6; b = 24; c = -537.6;
Δ = b2-4ac
Δ = 242-4·6·(-537.6)
Δ = 13478.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-\sqrt{13478.4}}{2*6}=\frac{-24-\sqrt{13478.4}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+\sqrt{13478.4}}{2*6}=\frac{-24+\sqrt{13478.4}}{12} $
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